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Comment:Added dummy first argument (comp_type) to cr
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SHA3-256: c76c510fa6d1522d14609285f25e8ca3427371dfbfbd14f7da76740ca4f1d291
User & Date: gawthrop@users.sourceforge.net on 2003-01-09 09:57:42
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Context
2003-01-15
16:49:10
New structure conversion script check-in: e24d9c6a3f user: gawthrop@users.sourceforge.net tags: origin/master, trunk
2003-01-09
09:57:42
Added dummy first argument (comp_type) to cr check-in: c76c510fa6 user: gawthrop@users.sourceforge.net tags: origin/master, trunk
2003-01-07
21:47:35
Added causal stroke information to ibg.m check-in: 99a7320daf user: geraint@users.sourceforge.net tags: origin/master, trunk
Changes
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Modified mttroot/mtt/lib/cr/r/cr.cr from [8711e303bd] to [df142395b3]. 

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%SUMMARY cr generic CR
%DESCRIPTION Argument is an algebraic expression with no embeddedwhite space
%DESCRIPTION Only available for one ports just now
%DESCRIPTION effort (or integrated effort) variable must be called mtt_e
%DESCRIPTION flow (or integrated flow) variable must be called mtt_f
%DESCRIPTION For example:
%DESCRIPTION             mtt_e=k*mtt_f
%DESCRIPTION             mtt_f=mtt_e/r

% $Log$



% Revision 1.3  2000/10/05 10:13:00  peterg
% New eqn2ass function.
% Started extension to multiports
%
% Revision 1.2  2000/10/03 18:35:04  peterg
% Removed comment bug
%
% Revision 1.1  2000/10/03 18:34:00  peterg
% Initial revision
%

%Copyright (C) 2000 by Peter J. Gawthrop


% Function to convert equation to assignment
OPERATOR eqn2ass;
FOR ALL eqn,outlist,inputs 
LET eqn2ass(eqn,outlist,inputs) =
BEGIN
    ass := {}; mtt_ports := 0;
    solutions := solve(eqn,outlist);
    FOR EACH solution IN solutions DO
    BEGIN
       mtt_ports := mtt_ports + 1;











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%SUMMARY cr generic CR
%DESCRIPTION Argument is an algebraic expression with no embeddedwhite space
%DESCRIPTION Only available for one ports just now
%DESCRIPTION effort (or integrated effort) variable must be called mtt_e
%DESCRIPTION flow (or integrated flow) variable must be called mtt_f
%DESCRIPTION For example:
%DESCRIPTION             mtt_e=k*mtt_f
%DESCRIPTION             mtt_f=mtt_e/r

% $Log$
% Revision 1.4  2000/12/28 09:18:38  peterg
% put under RCS
%
% Revision 1.3  2000/10/05 10:13:00  peterg
% New eqn2ass function.
% Started extension to multiports
%
% Revision 1.2  2000/10/03 18:35:04  peterg
% Removed comment bug
%
% Revision 1.1  2000/10/03 18:34:00  peterg
% Initial revision
%

%Copyright (C) 2000 by Peter J. Gawthrop


% Function to convert equation to assignment
OPERATOR eqn2ass;
FOR ALL comp_type, eqn,outlist,inputs 
LET eqn2ass(eqn,outlist,inputs) =
BEGIN
    ass := {}; mtt_ports := 0;
    solutions := solve(eqn,outlist);
    FOR EACH solution IN solutions DO
    BEGIN
       mtt_ports := mtt_ports + 1;
︙︙
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% We need four versions so that state does not need to be explicitly
% mentioned.
% At the moment, assume only one solution (in fact the first is
% chosen)

%%%% This is the Equation version
% Flow input
FOR ALL mtt_cr, input, out_cause
LET cr(mtt_cr,out_cause, 1, input, flow, 1) 
      = eqn2ass(mtt_cr,mtt_e,{mtt_f=input});

% Effort input
FOR ALL mtt_cr, input, out_cause
LET cr(mtt_cr,out_cause, 1, input, effort, 1)
    = eqn2ass(mtt_cr,mtt_f,{mtt_e=input});

% Effort output
FOR ALL mtt_cr, input, in_cause
LET cr(mtt_cr,effort, 1, input, in_cause, 1) 
    = eqn2ass(mtt_cr,mtt_e,{mtt_f=input});

% Flow output
FOR ALL mtt_cr, input, in_cause
LET cr(mtt_cr,flow, 1, input, in_cause, 1) 
    = eqn2ass(mtt_cr,mtt_f,{mtt_e=input});

%%%% This is the assignment version
% Flow input
FOR ALL mtt_cr_e,mtt_cr_f, input, out_cause
LET cr(mtt_cr_e,mtt_cr_f,out_cause, 1, input, flow, 1) 
    = sub(mtt_f=input,mtt_cr_f);

% Effort input
FOR ALL mtt_cr_e,mtt_cr_f, input, out_cause
LET cr(mtt_cr_e,mtt_cr_f,out_cause, 1, input, effort, 1) 
    = sub(mtt_e=input,mtt_cr_e);

% Effort output
FOR ALL mtt_cr_e,mtt_cr_f, input, in_cause
LET cr(mtt_cr_e,mtt_cr_f,effort, 1, input, in_cause, 1) 
    = sub(mtt_f=input,mtt_cr_f);

% Flow output
FOR ALL mtt_cr_e,mtt_cr_f, input, in_cause
LET cr(mtt_cr_e,mtt_cr_f,flow, 1, input, in_cause, 1) 
    = sub(mtt_e=input,mtt_cr_e);


%%% Q&D FMR 2 port.
FOR ALL mtt_cr_e,mtt_cr_f,input_1,input_2
LET cr(mtt_cr_e,mtt_cr_f,flow,1,
	input_1,effort,1,
	input_2,flow,2
	)  = sub(mtt_mod=input_2,sub(mtt_e=input_1,mtt_cr_e));

END;








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% We need four versions so that state does not need to be explicitly
% mentioned.
% At the moment, assume only one solution (in fact the first is
% chosen)

%%%% This is the Equation version
% Flow input
FOR ALL comp_type, mtt_cr, input, out_cause
LET cr(comp_type,mtt_cr,out_cause, 1, input, flow, 1) 
      = eqn2ass(mtt_cr,mtt_e,{mtt_f=input});

% Effort input
FOR ALL comp_type, mtt_cr, input, out_cause
LET cr(comp_type,mtt_cr,out_cause, 1, input, effort, 1)
    = eqn2ass(mtt_cr,mtt_f,{mtt_e=input});

% Effort output
FOR ALL comp_type, mtt_cr, input, in_cause
LET cr(comp_type,mtt_cr,effort, 1, input, in_cause, 1) 
    = eqn2ass(mtt_cr,mtt_e,{mtt_f=input});

% Flow output
FOR ALL comp_type, mtt_cr, input, in_cause
LET cr(comp_type,mtt_cr,flow, 1, input, in_cause, 1) 
    = eqn2ass(mtt_cr,mtt_f,{mtt_e=input});

%%%% This is the assignment version
% Flow input
FOR ALL comp_type, mtt_cr_e,mtt_cr_f, input, out_cause
LET cr(comp_type,mtt_cr_e,mtt_cr_f,out_cause, 1, input, flow, 1) 
    = sub(mtt_f=input,mtt_cr_f);

% Effort input
FOR ALL comp_type, mtt_cr_e,mtt_cr_f, input, out_cause
LET cr(comp_type,mtt_cr_e,mtt_cr_f,out_cause, 1, input, effort, 1) 
    = sub(mtt_e=input,mtt_cr_e);

% Effort output
FOR ALL comp_type, mtt_cr_e,mtt_cr_f, input, in_cause
LET cr(comp_type,mtt_cr_e,mtt_cr_f,effort, 1, input, in_cause, 1) 
    = sub(mtt_f=input,mtt_cr_f);

% Flow output
FOR ALL comp_type, mtt_cr_e,mtt_cr_f, input, in_cause
LET cr(comp_type,mtt_cr_e,mtt_cr_f,flow, 1, input, in_cause, 1) 
    = sub(mtt_e=input,mtt_cr_e);


%%% Q&D FMR 2 port.
FOR ALL comp_type, mtt_cr_e,mtt_cr_f,input_1,input_2
LET cr(comp_type,mtt_cr_e,mtt_cr_f,flow,1,
	input_1,effort,1,
	input_2,flow,2
	)  = sub(mtt_mod=input_2,sub(mtt_e=input_1,mtt_cr_e));

END;

MTT: Model Transformation Tools
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