Overview
Comment: | Initial revision |
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Downloads: | Tarball | ZIP archive | SQL archive |
Timelines: | family | ancestors | descendants | both | origin/master | trunk |
Files: | files | file ages | folders |
SHA3-256: |
c164ee2334a58f6b3285e552d2293aa4 |
User & Date: | gawthrop@users.sourceforge.net on 2000-10-03 18:34:00 |
Other Links: | branch diff | manifest | tags |
Context
2000-10-03
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18:35:04 | Removed comment bug check-in: 0f021d0c95 user: gawthrop@users.sourceforge.net tags: origin/master, trunk | |
18:34:00 | Initial revision check-in: c164ee2334 user: gawthrop@users.sourceforge.net tags: origin/master, trunk | |
18:29:57 | *** empty log message *** check-in: 7e955aef0a user: gawthrop@users.sourceforge.net tags: origin/master, trunk | |
Changes
Added mttroot/mtt/lib/cr/r/cr.cr version [bf8e268236].
> > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > | 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 | %SUMMARY cr generic CR %DESCRIPTION Argument is an algebraic expression with no embeddedwhite space %DESCRIPTION Only available for one ports just now %DESCRIPTION effort (or integrated effort) variable must be called mtt_e %DESCRIPTION flow (or integrated flow) variable must be called mtt_f %DESCRIPTION For example: %DESCRIPTION mtt_e=k*mtt_f %DESCRIPTION mtt_f=mtt_e/r % $Log$ %Copyright (C) 2000 by Peter J. Gawthrop % Version for one-port components operator cr; % We need four versions so that state does not need to be explicitly % mentioned. % At the moment, assume only one solution (in fact the first is chosen) % Flow input FOR ALL mtt_cr, input, out_cause LET cr(mtt_cr,out_cause, 1, input, flow, 1) = sub(mtt_f=input,rhs(first(solve(mtt_cr,mtt_e)))); % Effort input FOR ALL mtt_cr, input, out_cause LET cr(mtt_cr,out_cause, 1, input, effort, 1) = sub(mtt_e=input,rhs(first(solve(mtt_cr,mtt_f)))); % Effort output FOR ALL mtt_cr, input, in_cause LET cr(mtt_cr,effort, 1, input, in_cause, 1) = sub(mtt_f=input,rhs(first(solve(mtt_cr,mtt_e)))); % Flow output FOR ALL mtt_cr, input, in_cause LET cr(mtt_cr,flow, 1, input, in_cause, 1) = sub(mtt_e=input,rhs(first(solve(mtt_cr,mtt_f)))); END; |