游戏王残局简化版

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Check-in [155e05e63e]

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Comment:0.0.2550
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SHA3-256: 155e05e63ef09f490f159dcf2f2ab4a323abc4c7905eaea65aacac097452ea94
User & Date: 顽雨沉风 on 2023-09-15 02:59:32
Other Links: manifest | tags
Context
2023-09-15
03:05
0.0.2551 check-in: da30622ef9 user: 顽雨沉风 tags: trunk
02:59
0.0.2550 check-in: 155e05e63e user: 顽雨沉风 tags: trunk
02:57
0.0.2549 check-in: 6a4a8a79e5 user: 顽雨沉风 tags: trunk
Changes
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Modified 解法参考/MH-20210116.html from [2230dae9cd] to [9ffb0c66df].

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<pre><code>2 ^ 6 = 64

3 ^ 4 = 81

4 ^ 3 = 64</code></pre>
<p>至此，4 被淘汰</p>
<p>最优解为 3</p>
<p>但考虑到有些整数不能被 3 整数，故也需要 2</p>
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document.onclick = function(event) {

  var target = event.target

  if (target.tagName == "PRE"








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<pre><code>2 ^ 6 = 64

3 ^ 4 = 81

4 ^ 3 = 64</code></pre>
<p>至此，4 被淘汰</p>
<p>最优解为 3</p>
<p>但考虑到有些整数不能被 3 整除，故也需要 2</p>
<script>

document.onclick = function(event) {

  var target = event.target

  if (target.tagName == "PRE"
︙︙

Modified 解法参考/MH-20210116.md from [967a3bfbea] to [cad984696c].

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4 ^ 3 = 64
~~~

至此，4 被淘汰

最优解为 3

但考虑到有些整数不能被 3 整数，故也需要 2









|


38
39
40
41
42
43
44
45
46

4 ^ 3 = 64
~~~

至此，4 被淘汰

最优解为 3

但考虑到有些整数不能被 3 整除，故也需要 2