游戏王残局简化版

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    return u3, u4
  else
    return u1, u2
    end
  end
function s.历对(u1_0, u1, u2)
  local k1
  local h1_0, k2_0
  local h1_0, h2_0
  --~ 对
  h1_0 = {}
  for u3, u2_0 in pairs(u1_0) do
    --~ 键
    --~ 值
    k1, k2_0 = u1(u3, u2_0, u2)
    k1, h2_0 = u1(u3, u2_0, u2)
    if k1 then
      h1_0[k1] = k2_0
      h1_0[k1] = h2_0
    else
      end
    end
  return h1_0
  end
--~ 排中值
--~ 值类
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