%********************************************************************
module equivalence$
%********************************************************************
% Routines for testing equivalence of solutions
% Author: Thomas Wolf
% 1996
%
% $Id: crequsol.red,v 1.2 1998/04/28 21:32:11 arrigo Exp $
%
algebraic procedure extrfun(sol)$
% unpacking the free functions from the list of free functions
% together with their dependencies
for each f in third sol collect <<
for each h in rest f do depend first f,h;
first f
>>$
algebraic procedure equivsol(sol1,sol2,vl)$
% checking equivalence of two solutions of crack, that have been
% `completed' with the procedure `completesol' before.
% The evaluated functions should have identical names in both
% solutions. None of both solutions should contain any unsolved
% equations.
% vl is a list of all independent variables in both solutions.
begin
scalar f1,f2,s1,s2,ff2,f,h,s,v,mm_,oldtime;
symbolic fluid '(time_);
if (first sol1 neq {}) or
(first sol2 neq {}) or
(length second sol1 neq length second sol2) or
(length third sol1 neq length third sol2) then return nil;
f1:=extrfun(sol1);
f2:=extrfun(sol2);
% substituting the names of free functions in sol2 to avoid
% name clashes
s2:=second sol2;
ff2:=for each f in f2 collect <<
h:=lisp gensym();
s2:=sub(f=h,s2);
s:=fargs(f);
for each v in s do depend h,v;
h
>>;
% conditions of equivalence of both solutions
s1:=for each s in second sol1 collect (lhs s - rhs s);
s1:=sub(s2,s1);
lisp<<oldtime:=time_;time_:=nil>>;
h:=crack(s1,{},f1,vl);
lisp(time_:=oldtime);
% is there a regular relation beetween the free functions
% of sol1 and sol2?
if h={} or (length h neq 1) then return nil
else h:=first h;
if (first h neq {}) or (third h neq {}) then return nil;
s2:=second h;
h:=length f1;
matrix m__(h,h);
for f:=1:h do for s:=1:h do
m__(f,s):=df(rhs part(s2,f),part(ff2,s));
% cleaning dependencies
for each h in ff2 do <<
s:=fargs(h);
for each v in s do nodepend h,v;
>>;
return if det m__=0 then nil
else t
end$
algebraic procedure completesol(sol)$
% substitutes in a list of solutions of crack the list of free or yet
% unevaluated functions by a list of lists containing each function
% and the variables they depend on. This is useful to save solutions
% in files.
list(first sol,
second sol,
for each f in third sol collect cons(f,fargs f),
if length sol>3 then part(sol,4)
else {}
)$
endmodule$
end$