Overview
Comment: | 202408 found the antinodes; counting to do |
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Downloads: | Tarball | ZIP archive | SQL archive |
Timelines: | family | ancestors | descendants | both | trunk |
Files: | files | file ages | folders |
SHA3-256: |
ce30145a0dbabcb6b0aa81c654068fcd |
User & Date: | nnz on 2024-12-08 15:25:40 |
Other Links: | manifest | tags |
Context
2024-12-08
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16:02 | 202408 1st star check-in: 6c8d6b453f user: nnz tags: trunk | |
15:25 | 202408 found the antinodes; counting to do check-in: ce30145a0d user: nnz tags: trunk | |
15:03 | 202408 looking good so far check-in: ac43c4bcbc user: nnz tags: trunk | |
Changes
Modified Makefile from [e5558dd887] to [5fd029b772].
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Modified aoc2024.c from [e2e9f14685] to [ffa5f1e4f3].
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9 10 11 12 13 14 15 | 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 | - + + + + - - - + + + + + + + + + + | /* === aoc202408 ======================================================= Oh! another square of text! Idea: for all points p with an antenna find all points q>p with a corresponding frequency. For each such pair calculate the 2 antinodes and add the resulting points (if not there already) to an array. The answer to Part One is the number of elements in the array |
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