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ebdeddb639 2023-09-15 31: <h1 class="title">MH-20210116</h1>
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ebdeddb639 2023-09-15 34: <ul>
ebdeddb639 2023-09-15 35: <li><a href="#原解" id="toc-原解"><span class="toc-section-number">1</span> 原解</a></li>
d975a7f729 2023-09-15 36: <li><a href="#衍生" id="toc-衍生"><span class="toc-section-number">2</span> 衍生</a>
d975a7f729 2023-09-15 37: <ul>
d975a7f729 2023-09-15 38: <li><a href="#问" id="toc-问"><span class="toc-section-number">2.1</span> 问</a>
d975a7f729 2023-09-15 39: <ul>
d975a7f729 2023-09-15 40: <li><a href="#答" id="toc-答"><span class="toc-section-number">2.1.1</span> 答</a></li>
d975a7f729 2023-09-15 41: <li><a href="#解" id="toc-解"><span class="toc-section-number">2.1.2</span> 解</a></li>
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ebdeddb639 2023-09-15 46: <h1 data-number="1" id="原解"><span class="header-section-number">1</span> 原解</h1>
ebdeddb639 2023-09-15 47: <pre><code>1 * 5 = 5
ebdeddb639 2023-09-15 48:
ebdeddb639 2023-09-15 49: 2 * 4 = 8
ebdeddb639 2023-09-15 50:
ebdeddb639 2023-09-15 51: 3 * 3 = 9</code></pre>
ebdeddb639 2023-09-15 52: <h1 data-number="2" id="衍生"><span class="header-section-number">2</span> 衍生</h1>
d975a7f729 2023-09-15 53: <h2 data-number="2.1" id="问"><span class="header-section-number">2.1</span> 问</h2>
ebdeddb639 2023-09-15 54: <p>给定一个由数个小正整数累加起来的大正整数，问这些小正整数的值为多少才能让这些小正整数的累乘值最大</p>
d975a7f729 2023-09-15 55: <h3 data-number="2.1.1" id="答"><span class="header-section-number">2.1.1</span> 答</h3>
ebdeddb639 2023-09-15 56: <p>非 3 即 2</p>
d975a7f729 2023-09-15 57: <h3 data-number="2.1.2" id="解"><span class="header-section-number">2.1.2</span> 解</h3>
ebdeddb639 2023-09-15 58: <p>可能的值有 1 ~ 正无穷</p>
ebdeddb639 2023-09-15 59: <p>由指数爆炸性可知，只需要考虑 2 3 4</p>
da30622ef9 2023-09-15 60: <p>由 4 是 2 的倍数可知，只需要考虑 2 3</p>
da30622ef9 2023-09-15 61: <p>由某些正整数不能被 2 整除可知，需要 3</p>
da30622ef9 2023-09-15 62: <p>由某些正整数不能被 3 整除可知，需要 2</p>
da30622ef9 2023-09-15 63: <p>故，非 3 即 2</p>
da30622ef9 2023-09-15 64: <p>取 2 3 的最小公倍数 6</p>
da30622ef9 2023-09-15 65: <pre><code>2 ^ 3 = 8
da30622ef9 2023-09-15 66:
da30622ef9 2023-09-15 67: 3 ^ 3 = 9</code></pre>
da30622ef9 2023-09-15 68: <p>故，优先选 3</p>
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